Consecutive Integers

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Have you ever noticed how numbers on a calendar or pages in a book follow a special order? They are consecutive! Understanding consecutive integers is a foundational skill in algebra that helps solve fun puzzles and real-world problems. Let's explore these numbers that stick together!

Consecutive Integers — an original Algebra911 reference diagram defining consecutive integers with its key formula and a worked example.
Consecutive Integers: A Step-by-Step Guide

What Are Consecutive Integers?

Consecutive integers are integers that follow each other in order, without any gaps, just like counting. Each number is exactly one more than the number before it. Think about counting out loud: 1,2,3,4,. Those are consecutive integers!

Before we go further, let's remember what an integer is. An integer is any whole number. It can be positive (like 5 or 100), negative (like 3 or 25), or zero (0). Integers do not have fractions or decimals.

The word "consecutive" simply means "in a row." So, when we put them together, "consecutive integers" are whole numbers in a row.

  • 7,8,9 are three consecutive integers.
  • 25,26,27,28 are four consecutive integers.
  • 4,3,2 are three consecutive integers. Notice that they still go up by one each time (3 is one more than 4).
  • 1,0,1,2 are four consecutive integers, and they include zero!

What are NOT consecutive integers? Sets like 5,7,8 are not consecutive because there is a gap between 5 and 7. The number 6 is missing. Similarly, 10,11,13 are not consecutive. The key is that the difference between any two numbers right next to each other in the sequence must be exactly 1.

How Do We Represent Consecutive Integers Using Algebra?

This is where the fun begins! In algebra, we often use variables to represent unknown numbers. To solve word problems about consecutive integers, we need a way to write them using a variable, like n.

Let's say we don't know what our first integer is. We can just call it n. Since consecutive integers are always one apart, we can find the next ones by simply adding 1.

  • If our first integer is n,
  • The second integer must be n+1.
  • The third integer must be n+2.
  • The fourth integer must be n+3, and so on.

This pattern is a powerful tool. No matter what the first number (n) is, this representation will always give you a set of consecutive integers.

For a set of consecutive integers, we can represent them as:
n,n+1,n+2,n+3,

Let's test it. If we decide n=5, then our integers are:

  • n=5
  • n+1=5+1=6
  • n+2=5+2=7

We get the set 5,6,7, which are consecutive integers! If we pick a negative number, like n=10, we get:

  • n=10
  • n+1=10+1=9
  • n+2=10+2=8

The set is 10,9,8, which are also consecutive integers. This algebraic trick is the key to unlocking all kinds of word problems.

What About Consecutive Even and Odd Integers?

Sometimes, problems will ask about integers that are consecutive but are only even or only odd.

Consecutive even integers are even numbers that follow each other in order, like 8,10,12. Notice that you don't go up by one anymore. To get from one even number to the next, you have to skip the odd number in between, so you add 2.

Consecutive odd integers work the exact same way! They are odd numbers that follow each other in order, like 15,17,19. To get from one odd number to the next, you skip the even number, so you also add 2.

So, how do we write these using algebra? If we let our first number be n, the pattern is the same for both even and odd sets:

  • The first integer is n.
  • The second integer is n+2.
  • The third integer is n+4.
  • The fourth integer is n+6, and so on.

The important thing to remember is that if the problem asks for even integers, your starting number n must be even. If it asks for odd integers, your starting number n must be odd. The algebraic setup, however, looks identical.

Here is a table to help you remember the different representations:

Type of IntegersExampleAlgebraic Representation
(if n is the first number)
Consecutive5,6,7n,n+1,n+2
Consecutive Even10,12,14n,n+2,n+4
Consecutive Odd21,23,25n,n+2,n+4

Look closely at the table. The big mistake students make is thinking that odd integers should be represented with n+1,n+3, etc. But think about it: if your first odd number is n, how do you get to the very next odd number? You add 2, not 1. The same logic applies to even numbers. The jump is always 2!

How Do You Solve Problems with the Sum of Consecutive Integers?

Word problems involving consecutive integers often ask you to find the integers when you know their sum. To solve these, we can follow a simple four-step plan:

  1. Represent the Integers: Use the algebraic representations we just learned (n,n+1,n+2,).
  2. Write an Equation: Use the information in the problem (like the sum) to set up an equation.
  3. Solve the Equation: Use your algebra skills to find the value of n.
  4. Answer the Question: Use the value of n to find all the integers the problem asked for.

Let's walk through an example together.

Example 1

The sum of three consecutive integers is 63. Find the integers.

Step 1: Represent the Integers
The problem is about "three consecutive integers," so we will use the standard representation:
First integer: n
Second integer: n+1
Third integer: n+2

Step 2: Write an Equation
The problem says their "sum is 63." Sum means we need to add them all together. So, our equation is:
n+(n+1)+(n+2)=63

Step 3: Solve the Equation
First, combine the like terms on the left side. We have three n's (n+n+n) and the numbers 1 and 2.
3n+3=63
Now, we want to get n by itself. Subtract 3 from both sides:
3n+33=633
3n=60
Finally, divide both sides by 3:
3n3=603
n=20

Step 4: Answer the Question
We found that n=20, but the question asks for all three integers. We need to go back to our representations from Step 1:
First integer: n=20
Second integer: n+1=20+1=21
Third integer: n+2=20+2=22
So, the three consecutive integers are 20,21, and 22.

Final Check: Do they add up to 63? 20+21+22=63. Yes, they do! Our answer is correct.

Can We Solve Problems with Consecutive Even or Odd Integers?

Absolutely! The four-step process is exactly the same. The only thing that changes is Step 1, where we define our variables. Remember, for both consecutive even and consecutive odd integers, the difference between them is 2.

Let's try a problem with consecutive odd integers. Don't let the word "odd" trick you; the method is just as straightforward.

Example 2

The sum of three consecutive odd integers is 129. What are the integers?

Step 1: Represent the Integers
The problem specifies "three consecutive odd integers." We represent them by adding 2 each time:
First odd integer: n
Second odd integer: n+2
Third odd integer: n+4

Step 2: Write an Equation
The problem states that their "sum is 129." So, we add our representations:
n+(n+2)+(n+4)=129

Step 3: Solve the Equation
Combine the like terms on the left side. We have three n's and the numbers 2 and 4.
3n+6=129
Now, solve for n. Start by subtracting 6 from both sides:
3n+66=1296
3n=123
Now, divide both sides by 3:
3n3=1233
n=41

Step 4: Answer the Question
We found n=41. Is 41 an odd number? Yes! This is a good sign. Now we find all three integers:
First integer: n=41
Second integer: n+2=41+2=43
Third integer: n+4=41+4=45
The three consecutive odd integers are 41,43, and 45.

Final Check: Are they all odd? Yes. Are they consecutive? Yes. Do they sum to 129? 41+43+45=129. Perfect!

What If the Problem Is More Complicated?

Not all consecutive integer problems are about a simple sum. Some might involve multiplication or other relationships between the numbers. The key is to read the problem carefully and translate the English words into a mathematical equation. The four-step process still works perfectly.

Take your time breaking down the sentence piece by piece. Let's tackle a more challenging problem to see this in action.

Example 3

Find two consecutive even integers such that the sum of the smaller integer and twice the larger integer is 46.

Step 1: Represent the Integers
We need "two consecutive even integers."
Smaller even integer: n
Larger even integer: n+2

Step 2: Write an Equation
Let's break down the sentence: "the sum of the smaller integer and twice the larger integer is 46."
"the smaller integer" is n.
"twice the larger integer" is 2(n+2).
"the sum ... is 46" means we add them together to get 46.
The equation is:
n+2(n+2)=46

Step 3: Solve the Equation
First, use the distributive property on 2(n+2), which becomes 2n+4.
n+2n+4=46
Combine the n terms on the left:
3n+4=46
Now, we want to get the n term by itself. Subtract 4 from both sides:
3n+44=464
3n=42
Finally, divide by 3:
3n3=423
n=14
Since n=14 is an even number, our setup is working correctly.

Step 4: Answer the Question
We found n=14.
Smaller integer: n=14
Larger integer: n+2=14+2=16
The two consecutive even integers are 14 and 16.

Final Check: Is the sum of the smaller (14) and twice the larger (2×16=32) equal to 46? 14+32=46. Yes, it works! Our answer is correct.

What Are Some Common Mistakes to Avoid?

Working with consecutive integers is straightforward once you know the rules, but there are a few common traps to watch out for. Being aware of these will help you get the right answer every time!

  • Using the Wrong Representation: The most frequent mistake is using n,n+1,n+2 for consecutive even or odd integers. Remember, both even and odd integers are 2 apart, so you must use n,n+2,n+4.
  • Only Solving for n: It's easy to solve for n and feel like you're done. But the question almost always asks for the integers themselves. Always use your value of n to find all the numbers in the set.
  • Forgetting to Check the Type: If you solve a problem for consecutive odd integers and your value for n is an even number, you've likely made a mistake in your setup or calculation. The numbers you find must match the type (even or odd) requested in the problem.
  • Distribution Errors: In more complex problems, you might have to use the distributive property, like in 3(n+2). A common error is to forget to multiply the 3 by both terms inside the parentheses, resulting in 3n+2 instead of the correct 3n+6.
  • Answering the Wrong Question: Sometimes a problem will ask for the "largest of the three integers" or the "smallest integer." Make sure your final answer is exactly what the question is asking for, not just the whole set.

Double-checking your work is the best way to catch these small errors before they lead to a wrong answer.

A Quick Reference Guide

Here is a quick summary of the most important concepts from this lesson. You can use this as a reference sheet when you're doing practice problems.

Key Definitions

  • Integer: A whole number, which can be positive, negative, or zero (e.g., 5,0,12).
  • Consecutive: In order, one after another, without skipping.

Algebraic Representations

Consecutive Integers
n,n+1,n+2,
Consecutive Even OR Odd Integers
n,n+2,n+4,

Problem-Solving Steps

  1. Define Your Variables: Choose the correct algebraic representation for the integers.
  2. Write the Equation: Translate the word problem into a mathematical equation.
  3. Solve for n: Use algebra to find the value of the first integer, n.
  4. Find All Integers: Substitute the value of n back into your representations to find every integer.
  5. Check Your Answer: Make sure your numbers are the right type (even/odd) and that they satisfy the conditions of the original problem.

Frequently Asked Questions

Can consecutive integers be negative?

Yes, absolutely! Consecutive integers can be positive, negative, or include zero. For example, 5,4,3 is a set of three consecutive negative integers because they follow each other in counting order.

Is zero considered an integer in these problems?

Yes, zero is an integer. It can be part of a set of consecutive integers, such as 1,0,1. It is also considered an even number.

What is the algebraic expression for four consecutive integers?

If you let the first integer be n, then the next three would be one, two, and three greater. So, the representation for four consecutive integers is n,n+1,n+2,n+3.

How do you represent three consecutive odd integers?

You represent them by starting with an odd number n and adding 2 for each subsequent number. The algebraic representation is n,n+2,n+4, which is the same setup used for consecutive even integers.

Why is the difference between consecutive odd integers 2?

The difference is 2 because to get from one odd number to the next one, you must skip over the even number that lies between them. For example, to get from 7 to 9, you skip 8, which is a jump of two.

Is there a fast way to find the sum of consecutive integers?

Yes, there is a shortcut! You can find the average of the first and last numbers in the set and then multiply that average by the count of numbers. For 5,6,7,8, the average of 5 and 8 is (5+8)/2=6.5. Since there are four numbers, the sum is 6.5×4=26.

What if my answer for 'n' is a fraction or decimal?

If you solve for n and get a fraction or decimal, you have likely made a calculation error. By definition, these problems are about integers (whole numbers), so n should always be an integer.

Do I have to use 'n' as my variable?

No, you can use any letter you like for your variable, such as x, a, or k. Mathematicians most commonly use n or x, but any letter will work just as well.